Python 单实例模式
链接到标题
class Singleton(object):
_instances = {}
def __new__(cls, *args, **kwargs):
if cls not in cls._instances:
cls._instances[cls] = super(Singleton, cls).__new__(cls, *args, **kwargs)
return cls._instances[cls]
class MySingleton(Singleton):
def __init__(self, val):
self.val = val
a = MySingleton(1)
b = MySingleton(1)
print a.val
print b.val
def find_num(matrix, num):
if not matrix:
return False
rows = len(matrix)
cols = len(matrix[0])
row, col = rows - 1, 0
while row >= 0 or col <= cols -1:
if matrix[row][col] == num:
return num
elif matrix[row][col] > num:
row -= 1
else:
col += 1
return False
matrix = [[1,2,3,4],
[5,6,7,8]
]
print find_num(matrix, 7)
class Links(self):
def __init__(self, x):
self.val = x
self.next = None
def print_links(links):
if links:
print_links(links.next)
print links.val
links = Links(1)
links.next = Links(2)
links.next.next = Links(3)
print_links(links)
# 根据前序和中序遍历结果构建二叉树,遍历结果中不包含重复数值。
class TreeNode(object):
def __init__(self, x):
self.val = x
self.left = None
self.right = None
class Tree(object):
def __init__(self):
self.root = None
def pre_traversal(self):
ret = []
def traversal(head):
if not head:
return
ret.append(head.val)
traversal(head.left)
traversal(head.right)
traversal(self.root)
return ret
def in_traversal(self):
ret = []
def traversal(head):
if not head:
return
traversal(head.left)
ret.append(head.val)
traversal(head.right)
traversal(self.root)
return ret
def post_traversal(self):
ret = []
def traversal(head):
if not head:
return
traversal(head.left)
traversal(head.right)
ret.append(head.val)
traversal(self.root)
return ret
def construct_tree(preorder=None, inorder=None):
if not preorder or not inorder:
return None
index = inorder.index(preorder[0])
left = inorder[0:index]
right = inorder[index + 1:]
root = TreeNode(preorder[0])
root.left = construct_tree(preorder[1:1+len(left)], left)
root.right = construct_tree(preorder[-len(right):], right)
return root
t = Tree()
root = construct_tree(preorder=[1,2,4,7,3,5,6,8],
inorder=[4,7,2,1,5,3,8,6])
t.root = root
print t.pre_traversal()
print t.in_traversal()
print t.post_traversal()
def find_min(nums):
if not nums:
return False
length = len(nums)
left, right = 0, length - 1
while nums[right] >= nums[left]:
if right - left == 1:
return nums[right]
mid = (left + right) / 2
if nums[left] <= nums[mid]:
left = mid
if nums[right] >= nums[mid]:
right = mid
return nums[0]
nums = [3,4,5,6,0,1,2]
print find_min(nums)
nums = [1,0,0,1]
print find_min(nums)
二进制中 1 的个数
链接到标题
def find_num_of_1(n):
ret = 0
if n < 0:
n = n & 0xffffffff
while n:
ret += 1
n = n & (n - 1)
return ret
num = 3
print find_num_of_1(num)