…v = arr[i - 1] curr = abs(prev - arr[i]) if curr < m: out = prev, arr[i] m = curr elif curr == m: out.append([prev, arr[i]]) return out…
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1 篇文章提到了此关键词
…v = arr[i - 1] curr = abs(prev - arr[i]) if curr < m: out = prev, arr[i] m = curr elif curr == m: out.append([prev, arr[i]]) return out…